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Posted by / 06-Sep-2017 11:08

No logging nude chats

Now let us consider a situation where a drill string section is present in the wellbore as shown in the figure below.

When the drill string is in tension, it tries to straighten while going around a dogleg.

The drill string exerts a force on the formation as shown in figure.

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Since the inclination is constant (refer rows in the table below) and only the azimuth changes, thus, substituting the values of I, A and MD in Equation 1 and calculating DLS, the result obtained is as tabulated below : One can easily imagine a situation when DLS is high ..

You can even perform a home based experiment to experience this situation.

As drilling continues, the drill string tension in the dogleg increases which increases the lateral force.

The lateral force causes the drill string to cut into the wellbore wall at the dogleg (refer figure below).

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